Let me explain...
My dad decided to take me out to dinner and a play. We ate at Cedar Creek Inn in Laguna Beach...delicious...and there was this sweet little old couple in the booth next to us...they had to be at least 80 years old an the woman's wine glass was bigger than her...and I'm pretty sure the old man was sitting on a booster seat. Anyway, while at dinner I was noticing what an old crowd there was...and thought it was interesting because my previous dining experiences at Cedar Creek has not led on to the fact that it was a popular destination for leisure World Fun Night Outs.
Anyway, when we got to the play...it all made perfect sense. Please keep in mind that the following statements are neither made up, embellished, or fabricated in anyway. I was BY FAR the youngest person in the theater. From what I saw the next youngest person was probably in her late thirties...and my best guess would be that the AVERAGE age in the theater (the mean) was around 70 years old...[the median was probably 78...and the mode was definitely 80] You KNOW it's an old crowd when 75 year old men are helping the "older folk" down the stairs.
My dad said, "I guess this is the highlight of their month...going to a play at the Laguna Playhouse." I mean it made sense...the play was about war and a flashback to when a woman was young. Depressing really...the play and getting old.
As the great philosopher, John Mayer puts it: "So scared of getting older, I'm only good at being young." Stop this Train...listen to it. [sidenote] Seriously get the album...I've only had it for a few days...but I like it. I'll probably blog about more of his songs.
But..I'm sure being old will be just as much fun as being young.
2 comments:
do you think you could give me the variance so that I could take the square root and find the standard deviation, that way I can just use X minus Mew divided by the standard deviation to find the Z score and then find the probability of there being another person your age in the room. Unless it was a binomial distribution in which case I would need to know P so that I could find Q and I would need to know the number of people in the room (N) to then find the Z score as X minus X bar divided by standard deviation, this time not being Sigma, but rather S.
oh wait, is this a normal distribution?
My parents have season tickets to the Laguna Playhouse...they love it. They are in their mid-50's.
Sometimes I feel like hanging out with old people is good for me.
Oh yeah, is that the new John Mayer CD that you are talking about, Continum?
-Mike
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